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Join date: May 13, 2022

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If you don't have WinToUSB, this is the tool you need! WinToUSB is a powerful . This tool supports all versions of Windows, including the latest version. It also supports various Linux distributions, Win32/32-bit/64-bit, and Mac OS X. This tool will also let you create a bootable ISO image.Q: Python: Many ifs with and, or and not I'm new to python. Please explain this code. I know the 'else' part, that means that the else is a default. When I input the first number '1', '2', '3' or '4', I want to print "Choose an option", instead of "" when I input '5', '6', '7' or '8', I want to print "Choose another option". when I input the others, I want to print the normal output. Is this true, and if not, please explain Thank you A: You can use an if-else statement with a default to avoid multiple ifs. for i in range(1, 9): if i == 1 or i == 2 or i == 3 or i == 4: print "Choose an option" else: print "Choose another option" In python you can choose a variable number of alternatives using tuples print "Choose an option", "Choose another option" print "Choose an option" if i == 1 or i == 2 or i == 3 or i == 4 else "Choose another option" I guess you are used to programming in C++/Java/C#, not C. Also, if you want to write a loop that can deal with variable numbers of options you could use an enumeration from enum import Enum class Choice(Enum): OPTION_1 = 1 OPTION_2 = 2 OPTION_3 = 3 OPTION_4 = 4 choice = Choice.OPTION_1 while choice!= Choice.OPTION_2 or choice!= Choice.OPTION_3 or choice!= Choice.OPTION_4: print "Choose an option




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